Complex Functions

Complex Functions

A function of a complex number is a function f:\mathbb{C} \rightarrow \mathbb{C}, that is f(z) = w where z = x + yi, w = u(x,y) + v(x,y)i. A complex function is a pair of real functions put together (analogous to a complex number being comprised of real numbers). For example, f(z) = z^2 = (x^2 - y^2) + 2xyi = u(x,y) + v(x,y)i.

Holomorphic function
f(z) is holomorphic (analytic, regular) in a region R of the complex plane if it has a unique derivative at every point in R.
Derivative of a complex function
This has the usual definition, f'(z) = \frac{df}{dz} = \lim_{h \rightarrow \infty} \frac{f(z+h)-f(z)}{h}. However, for the derivative to exist it has to meet more stringent requirements. Recall that for a real function, the derivative exists iff the right and left derivatives exist and are equal. However, since complex functions exist in the complex plane (which is two dimensional), we need the left, right, up, down and diagonal limits to exist and to be equal.
Cauchy-Riemann Relations
\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \qquad \frac{\partial u}{\partial y} = \frac{\partial v}{\partial x}
Theorem
If f(z) = u(x,y) + v(x,y)i is holomorphic in a region R, then u and v satisfy the Cauchy-Riemann relations. The relations are thus a necessary, but not sufficient condition for f to be holomorphic.
Theorem
If \frac{\partial u}{\partial x}, \frac{\partial u}{\partial u}, \frac{\partial v}{\partial x}, \frac{\partial v}{\partial y} exist, are continuous and satisfy the Cauchy-Riemann relations in a region R \subseteq \mathbb{C}, then f(z) = u(x,y) + v(x,y)i is holomorphic in R.
Theorem
If f(z) is holomorphic in a region R of the complex plane, then it has derivatives of all orders at all points in R i.e. it will be infinitely differentiable.
Theorem
If f(z) is holomorphic in R, then it can be expanded as a Taylor series around any point z_0 in R. Radius of convergence of Taylor series around z_0 will be: R_\text{conv} = \min|z_0 - z_s|, where z_s is a singular point of f(z) (i.e. a point where f is not holomorphic, its complex derivative is undefined)
Theorem
If f(z) = u(x,y) + v(x,y)i is a holomorphic in a region R, then u and v satisfy Laplace’s equation in R: \nabla^2 u = 0, \quad \nabla^2v = 0. If f is holomorphic then u and v are considered harmonic functions (since they satisfy Laplace’s equation). Thus, if g and h satisfy Laplace’s equation, then they can serve as the real or imaginary parts of a holomorphic complex function.

Complex Integrals and Cauchy’s Theorem

To integrate f(z) from point a to point b where a,b \in \mathbb{C}, we have to consider what is essentially the line integral of the function between a and b.

Suppose f(z) = u + vi where z = x + yi. The path C from a to b can be parametrized as x = x(t), y = y(t) \qquad t \in [a,b].

Now, write x' = \frac{dx}{dt}, y' = \frac{dy}{dt}.

Then, \begin{aligned} \int_C f(z) dz &= \int_C (u+vi)(dx + idy) \\ &= \int_C udx - \int_C vdy + i \int_C udy + i\int_C vdx \\ &= \int_a^b u x'dt - \int_a^b vy'dt + i \int_a^b uy'dt + i\int_a^b vx'dt\\ \end{aligned}

Cauchy’s Theorem
Relates to contour integration. Suppose f(z) is a complex function and C is a closed curve in the complex plane. If the following conditions are satisfied: then, \oint_C f(z)dz = 0.
Cauchy Integral Formula
If f(z) is holomorphic on or inside a simple closed curve C, then: f(a) = \frac{1}{2\pi i} \oint_C \frac{f(z)}{z-a}dz, where a is inside C. If a is outside C, the integral will evaluate to 0.

Laurent Series

Generalised Taylor series for complex functions.

Laurent’s Theorem
Suppose that R is a region enclosed by two concentric circles (of any size). Suppose further that f(z) is holomorphic in R. Then f(z) = \sum_{k=0}^{\infty} a_k (z - z_0)^k + \sum_{j=1}^{\infty}b_j (z-z_0)^{-j}\\ = a_0 + a_1(z-z_0) + \ldots + \frac{b_1}{z-z_0} + \frac{b_2}{z-z_0} + \ldots, which is the sum of the analytic part (a terms) and the principal part (b terms).

Now to find the coefficients of a Taylor series, you find the derivatives of f(x) at the point about which expansion occurs. For a Laurent series, you have to use contour integrals to calculate the coefficients.

For the analytic part, a_n = \frac{1}{2\pi i} \oint_C \frac{f(z)}{(z-z_0)=^{n+1}} dz. For the principal part, b_n = \frac{1}{2\pi i} \oint_C \frac{f(z)}{(z-z_0)=^{-n+1}} dz. Here, C is a closed curve inside R that surrounds z_0.

Notes/definitions about poles/singularities/residues…

Residue Theorem

Suppose f(z) is a complex function with many singular points, z_1, z_2, ..., z_n. If C is a curve that encloses all these points, then \oint_{C}f(z)dz = 2\pi i \sum_{j=0}^{n}b_{ij}.

References

Faculty of Khan YouTube series